1867 Minnesota lieutenant gubernatorial election
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November 5, 1867
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The 1867 Minnesota lieutenant gubernatorial election was held on November 5, 1867, in order to elect the lieutenant governor of Minnesota. Republican nominee and incumbent lieutenant governor Thomas H. Armstrong defeated Democratic nominee Arba Maynard.[1]
General election
On election day, November 5, 1867, Republican nominee Thomas H. Armstrong won re-election by a margin of 5,773 votes against his opponent Democratic nominee Arba Maynard, thereby retaining Republican control over the office of lieutenant governor. Armstrong was sworn in for his second term on January 8, 1868.[2]
Candidates
- Arba Maynard, Member of the Minnesota House of Representatives (Democratic)
- Thomas H. Armstrong, Incumbent (Republican)
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | Thomas H. Armstrong (incumbent) | 35,056 | 54.48 | |
| Democratic | Arba Maynard | 29,283 | 45.51 | |
| Scattering | 8 | 0.01 | ||
| Total votes | 64,347 | 100.00 | ||
| Republican hold | ||||
References
- ↑ "Lieutenant Governor, 1867 Election". electionarchives.lib.umn.edu. Retrieved 2024-09-26.
- ↑ "MN Lieutenant Governor". ourcampaigns.com. March 18, 2024. Retrieved 2024-09-26.