1856 Rhode Island gubernatorial election
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April 2, 1856
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 County results Hoppin: 50–60% 60–70% | |||||||||||||||||
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| Elections in Rhode Island |
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The 1856 Rhode Island gubernatorial election was held on April 2, 1856, to elect the governor of Rhode Island. Incumbent Republican governor William W. Hoppin won re-election over Democratic nominee Americus V. Potter in a rematch from the 1855 Rhode Island gubernatorial election.[1]
General election
Incumbent Whig governor William W. Hoppin had changed parties before the election and instead joined the Republican party, by being the incumbent governor, Hoppin's quickly became the Republican nominee for re-election. On election day, April 2, 1856, incumbent Republican governor William W. Hoppin won reelection by a margin of 2,734 votes against his Democratic opponent Americus V. Potter, thereby retaining Republican control over the office of governor. Hoppin was sworn in for his third term on May 26, 1856.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Republican | William W. Hoppin (incumbent) | 9,865 | 57.95 | |
| Democratic | Americus V. Potter | 7,131 | 41.89 | |
| Scattering | 27 | 0.16 | ||
| Total votes | 17,023 | 100.00 | ||
| Republican hold | ||||
References
- ↑ McLoughlin, William G (1986). Rhode Island: A History. New York: W.W. Norton & Company. pp. 141–142. ISBN 0-393-30271-7.
- ↑ "RI Governor". ourcampaigns.com. June 6, 2005. Retrieved 2023-05-10.