1810 Connecticut Secretary of the State election
April 9, 1810
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The 1810 Connecticut Secretary of the State election was held on April 9, 1810, in order to elect the Secretary of the State of Connecticut. Federalist candidate Thomas Day won the election against Democratic-Republican candidate Henry Seymour and fellow Federalist candidate Thomas Chester.[1]
General election
On election day, April 9, 1810, Federalist candidate Thomas Day won the election by a margin of 3,673 votes against his foremost opponent Democratic-Republican candidate Henry Seymour, thereby retaining Federalist control over the office of Secretary of the State. Day was sworn in for his first term on May 10, 1810.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Federalist | Thomas Day | 6,383 | 63.70 | |
| Democratic-Republican | Henry Seymour | 2,710 | 27.10 | |
| Federalist | Thomas Chester | 471 | 4.70 | |
| Scattering | 450 | 4.50 | ||
| Total votes | 10,014 | 100.00 | ||
| Federalist hold | ||||
References
- ↑ "Connecticut 1810 Secretary of State". elections.lib.tufts.edu. January 11, 2012. Retrieved 2026-04-13.
- ↑ "1810 Apr 9 :: General Election :: Secretary of the State :: State of Connecticut". electionhistory.ct.gov. 2016. Retrieved 2026-04-13.
Categories:
- 1810 Connecticut elections
- 1810 in Connecticut
- Connecticut Secretary of State elections
- April 1810
- 1810 elections
- 1810 elections in North America
- 1810 elections in the United States
- 1810s Connecticut elections
- 1810s in Connecticut
- 1810s elections
- 1810s elections in North America
- 1810s elections in the United States
- 19th-century elections
- 19th-century elections in North America
- 19th-century elections in the United States
- 19th century in Connecticut
- Government of Connecticut

