Manzanita Peak
| Manzanita Peak | |
|---|---|
  Manzanita Peak Location within Alaska | |
| Highest point | |
| Elevation | 2,667 ft (813 m)[1] |
| Coordinates | 56°35′32″N 132°39′45″W / 56.59222°N 132.66250°W[2] |
| Geography | |
| Location | Petersburg Borough, Alaska, U.S. |
| Topo map | USGS Petersburg C-2 |
Manzanita Peak is a mountain in the eastern part of Mitkof Island, one of the islands in the Alexander Archipelago in Alaska. It is to the west of Favor Peak and northwest of Sam Peak.[1]
References
- 1 2 Petersburg C-2 quadrangle, Alaska (Map). 1:63360. 15 Minute Topographic. USGS. Retrieved February 7, 2009.
- ↑ "Manzanita Peak". Geographic Names Information System. United States Geological Survey, United States Department of the Interior. Retrieved February 7, 2009.